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Post by CooLiBoP on Mar 12, 2002 17:47:50 GMT -5
Can some1 explain to me #5 of last years test...I have the solution and it makes no sense to me whatsoever...I sort of get 5a) but b) and c) are just confusing...
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Post by gabbie on Mar 12, 2002 18:09:25 GMT -5
i think (a) is asking u to define the Lp(f) and Up(f) ?? and in the textbook, there are series of definitions for they part "... for f to be intergrable on [a,b]" (b) just find the Lp(f) and Up(f) use your partition to figure out with "height" of f is appropriate, either 1 or 2, since the graph jumps, for Lp(f) u use 1 ?? rite ? Up(f) use 2 ?? (c) i think it's in the textbook
sorry i don't think i am very helpful... i am most likely wrong as usual... btw, where did u get the anwers ? i only managed to get the questions..
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JebusMeany
Junior Member
Who is Jebus Meany?
Posts: 22
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Post by JebusMeany on Mar 12, 2002 23:36:31 GMT -5
I was just wondering if anyone had any good ideas on how to approach the hodge-podge type questions. I mean, some are obvious just by looking, (ie// if the denominator is of the form (a^2 - x^2)^1/2 you use a trig substitution), but there are some that are not. (re:entire PS#17) Any ideas would be cool, thanks!
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Post by Observer on Mar 12, 2002 23:45:43 GMT -5
Indeed, hodge-podge approachingness help much appreciated.
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Post by AngelLaura on Mar 13, 2002 0:42:59 GMT -5
Does anyone know the actual answer for #2?
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Post by CooLiBoP on Mar 13, 2002 13:07:56 GMT -5
Does anyone know the actual answer for #2? Yup... F'(2) = e 1(-1/4) = -e/4
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Post by AngelLaura on Mar 13, 2002 14:08:41 GMT -5
Yup... F'(2) = e 1(-1/4) = -e/4 Okay, how did you get this?
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Post by CooLiBoP on Mar 13, 2002 16:01:52 GMT -5
F'(x) = esqrt(1/[(x/1)^4-15]) (-1/x^2)
= esqrt(x^4 - 15) (-1/x^2)
=> F'(2) = e * -1/4 = -e/4
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