Term Test #2 Help (post your stupid Q's here)

[R]

Here are my stupid questions... I know these can be answered from the notes, but my notes are very messy...

1) When you approx rt 2 with the Newton Method, i have no idea why the prof choosed x^2-2 to begin with as f(x)

2)wtf is extrema? Is it abs and local max min?

3)whenever you found something that doesn't exist.. do u need to take its limit on both sides? (I think you do)

[R]

no one can answer my Q's?

or just dun't have to bother?

[1.8T]

R said:

1) When you approx rt 2 with the Newton Method, i have no idea why the prof choosed x^2-2 to begin with as f(x)

the equation x^2 -2  will equal zero when u sub rt2 as x,
hence rt2 is a root of that equation., which is what we want to approximate , when that function crosses the x axis.,

[Majin_Blues]

R said:

2)wtf is extrema? Is it abs and local max min?

3)whenever you found something that doesn't exist.. do u need to take its limit on both sides? (I think you do)

2)  extrema is plural for extremes... max, min, whatever you wanna call it/them...

3)  i think it's the other way around... according to the problem set solution, they checked limits for both sides (when it's no longer oo/oo or 0/0)...

question to number 3:  what if the limits are the same and it's in the form such that it cannot exist?  (e.g. 3/0, etc.) (i dunno if it's possible, but what if it comes up?)

[TheSearchIsOn]

R said:

3)whenever you found something that doesn't exist.. do u need to take its limit on both sides? (I think you do)

I believe what R is asking here is if we need to take the limit from both sides when we are checking for vertical asymptotes ie. graph f(x)= 1/(1-x) do we need to take the limit as x approaches 1 from both the left and right? If I'm getting a wrong interpretation of what he's asking could someone answer my question anyways?

[bAh]

TheSearchIsOn said:

I believe what R is asking here is if we need to take the limit from both sides when we are checking for vertical asymptotes ie. graph f(x)= 1/(1-x) do we need to take the limit as x approaches 1 from both the left and right? If I'm getting a wrong interpretation of what he's asking could someone answer my question anyways?

I believe that we DO have to take limit from both sides since we would be interested to find out which infinity (positive/negative) that f(x) approaches when x closes on to the vertical asymptote.

so when we are dealing with vertical asymptotes in graphing questions, we will be expected to check :

  lim        f(x) =  +/- oo
(x-> 1-)

  lim        f(x) =  +/- oo
(x-> 1+)

hope that i do answer ur question or i'm just plain stupid and interpreted the question wrong..  

[Brutal_Chicken]

Majin_Blues said:

question to number 3:  what if the limits are the same and it's in the form such that it cannot exist?  (e.g. 3/0, etc.) (i dunno if it's possible, but what if it comes up?)

Then the limit DNE... I think you're thinking too hard.  ;D

[SquirrelHunterPro]

OH GOD OH GOD OH GOD!!! I M TOAST!!!  

This test will be my undoing..... anyone know when is the final date we can drop a course with no penalty? i.e. be able to take MAT135 next year? he he he, I am taking human interaction instead of software engineering... just too brutal for me.

QUESTION: what do we do if a limit problem goes something like infinite times zero.... Igefeld said we can use L'hopital's rule... but I think he told us to do it as a homework exercise... anyone plz help! ! !

[L]

Does anyone know how to do question 5 or part 5 of question 1 from last year's test?

[Tiffany]

well, does anyone know that are we respond for the materials from test 1? Thx.

[Majin_Blues]

L said:

Does anyone know how to do question 5 or part 5 of question 1 from last year's test?

1) v)  because of the 1/5 exponent, you have to use binomial theorem to expand the top and bottom... it's crazy, and hard to explain

5)  let y = y, then examine the new equation using the solution to solve quadratic equations (use quadratic formula).  Then to have only one root (i.e. intersect only once), it means that root part in the quadratic formula has to be zero.  etc.

[Brutal_Chicken]

L said:

Does anyone know how to do question 5 or part 5 of question 1 from last year's test?

For 1V the way to do it is sub x = 1/t then use L'H's rule. For 5, 1 + mx is the same as x + 1/x when...? Well,

when 1 + mx = x + 1/x. which values of m will make this true? Bring it all over to one side, use the quadratic formula, and look for values of m where the number under the root (the discriminant) is 0.


Blues man, I'm taking Software Engineering too and I'm considering dropping out of it but it's already half-way done. Well, a quarter of the way done since CS guys need only two math courses, at least for SE. I think we can still drop it though. And remember, anything times 0 is 0; including infinity...

[Majin_Blues]

Brutal_Chicken said:

Blues man, I'm taking Software Engineering too and I'm considering dropping out of it but it's already half-way done. Well, a quarter of the way done since CS guys need only two math courses, at least for SE. I think we can still drop it though. And remember, anything times 0 is 0; including infinity...

cs people only need 2 math courses?  FOR REAL???  hmm... maybe i should stick with comp sci... but i kinda wanna go to commerce...

side note: oo x 0 does not necessarily = 0... remember those infinity limits?  it's times like those you flip one, then apply "the hospital"

[AngelLaura]

A probably stupid question, in that I think I may have asked it when we were doing the related PS, but oh well...

How do you know if a function has an oblique (slant) asymptote? I know how to find it, but what sort of evidence makes it clear that one exists?

Thanks,
Laura.

[Rogue_Knight]

Slant asymptotes only appear when the numerator is one power of x larger than then denominator.
ie)      x^ n + c
     -------------
       x^n-1 + d

where c and d are the rest of the function which doesn't matter when it comes to asymptotes.
This is the only situation where a slant asymptote appears, however, if the remainder from your division is not a straight line, then you don't have a slant asymptote.

- Lou