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Post by Brutal_Chicken on Jan 16, 2002 6:45:00 GMT -5
So, say something like x^3 / (x-1)^2. How does one divide that?
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Post by Majin_Blues on Jan 16, 2002 8:04:48 GMT -5
expand the denominator, then do division with equations...
if you don't want to divide, there's another method:
asymptote has the equation y = ax + b
where:
lim f(x) a = x->oo ----- x
and lim b = x->oo |f(x) - x|
(and i thought you find slant asymptotes if there's no horizontal asymptote?)
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Post by Brutal_Chicken on Jan 16, 2002 13:18:24 GMT -5
I think you forgot an 'a' coefficient for x there... Thanks by the way. That jogged the memory.
If there's a horizontal asymptote then => no slant asymptote. If there's a slant then => no horizontal. BUT, just because there isn't a horizontal doesn't mean there's a slant.
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