wonginator
Junior Member
ignorance is bliss
Posts: 9
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#4
Mar 26, 2002 15:22:46 GMT -5
Post by wonginator on Mar 26, 2002 15:22:46 GMT -5
umm, yah #4?? help please
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#4
Mar 26, 2002 21:38:23 GMT -5
Post by Brutal_Chicken on Mar 26, 2002 21:38:23 GMT -5
They're actually 'holding your hand' in this one, telling you exactly what you have to do.
Basically, what you're trying to do is to prove that it converges. It converges iff it's constantly increasing or decreasing AND if it's bounded by some theorem. You prove both by induction.
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Achilles
Junior Member
Heh,heh, heh
Posts: 24
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#4
Mar 26, 2002 23:28:29 GMT -5
Post by Achilles on Mar 26, 2002 23:28:29 GMT -5
p.600: Thm 10.3.6 they say "a bounded, nondecreasing seq converges to its least upper bond, etc." so that means a sequence doesn't have to be increasing to converge, just nondecreasing. What do you mean some Thm? ?
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#4
Mar 27, 2002 15:21:34 GMT -5
Post by Brutal_Chicken on Mar 27, 2002 15:21:34 GMT -5
What that means is I was too lazy to look it up...
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#4
Mar 28, 2002 0:14:46 GMT -5
Post by R on Mar 28, 2002 0:14:46 GMT -5
for #4 b, do we use strong induction? or just show?
I think strong induction makes more sense, but I'm a lazy slacker and I dun't have time. Plus, I forgot how to do strong MI
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#4
Mar 28, 2002 2:18:43 GMT -5
Post by Rogue_Knight on Mar 28, 2002 2:18:43 GMT -5
you can do this with simple induction
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hehe....
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#4
Mar 28, 2002 2:39:29 GMT -5
Post by Rogue_Knight on Mar 28, 2002 2:39:29 GMT -5
lim n--> infinity an = L V e>0, E N>0 S.T. if n>N then |an - L| < e
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